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8x^2-51x-35=0
a = 8; b = -51; c = -35;
Δ = b2-4ac
Δ = -512-4·8·(-35)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-61}{2*8}=\frac{-10}{16} =-5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+61}{2*8}=\frac{112}{16} =7 $
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